1D Manholes: Difference between revisions
Content deleted Content added
Tuflowduncan (talk | contribs) |
Tuflowduncan (talk | contribs) |
||
Line 144:
Which matches the value in figure x.
===Example 2 - Exit Losses===
In this example, A'<sub>m</sub> is 4.12m<sup>2</sup>, therefore K<sub>exit</sub>:[[File:K exit2.PNG]]
Which matches the result in figure x.
===Example 2 - Outgoing Conduit Losses===
On this occasion, we have an 90 degree angle between the incoming and outgoing conduit. Therefore, we need to calculate Kθ using the following equation: [[File:Ktheta.PNG]]
Q<sub>f</sub> is calculated as: [[File:Qf.PNG]]
Q<sub>p</sub> and Q<sub>om</sub> are both 2m<sup>3</sup>s<sup>-1</sup> and therefore Q<sub>f</sub> is equal to 1. The incoming conduit angle is 90 degrees which is cancelled out by the denominator. K<sub>θ</sub> is therefore:[[File:Ktheta1.PNG]]
We also have a drop between the incoming and outgoing pipes. K<sub>drop</sub> which represents losses due to this drop is calculated as follows:[[File:Kdrop.PNG]]
Which is:[[File:Kdrop 1.PNG]]
Therefore K<sub>outletpipe</sub> is:[[File:K outletpipe2.PNG]]
This matches the simulated value in figure x.
=Storage chambers=
| |||