Revision as of 20:34, 25 May 2021 view source Tuflowduncan (talk \| contribs) Bureaucrats, Administrators 1,219 edits →Example 2 Exit Losses ← Older edit		Revision as of 20:35, 25 May 2021 view source Tuflowduncan (talk \| contribs) Bureaucrats, Administrators 1,219 edits →Example 2 - Outgoing Conduit Losses Newer edit →
Line 152: ===Example 2 - Outgoing Conduit Losses=== On this occasion, we have an 90 degree angle between the incoming and outgoing conduit. Therefore, we need to calculate Kθ using the following equation: [[File:Ktheta.PNG]] <br> Q<sub>f</sub> is calculated as: [[File:Qf.PNG]] <br> Q<sub>p</sub> and Q<sub>om</sub> are both 2m<sup>3</sup>s<sup>-1</sup> and therefore Q<sub>f</sub> is equal to 1. The incoming conduit angle is 90 degrees which is cancelled out by the denominator. K<sub>θ</sub> is therefore:[[File:Ktheta1.PNG]]

1D Manholes: Difference between revisions