Manhole Simple Loss Example: Difference between revisions
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===Example 2 - Outgoing Conduit Losses===
On this occasion, we have an 90 degree angle between the incoming and outgoing conduit. Therefore, we need to calculate Kθ using the following equation:<br> [[File:Ktheta.PNG]]<br>
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Q<sub>f</sub> is calculated as:<br> [[File:Qf.PNG]]
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Q<sub>p</sub> and Q<sub>om</sub> are both 2m<sup>3</sup>s<sup>-1</sup> and therefore Q<sub>f</sub> is equal to 1. The incoming conduit angle is 90 degrees which is cancelled out by the denominator. K<sub>θ</sub> is therefore:<br>[[File:Ktheta1.PNG]]<br>
We also have a drop between the incoming and outgoing pipes. K<sub>drop</sub> which represents losses due to this drop is calculated as follows:<br>[[File:Kdrop.PNG]]<br>
Which is:<br>[[File:Kdrop 1.PNG]]<br>
Therefore K<sub>outletpipe</sub> is:<br>[[File:K outletpipe2.PNG]]<br>
This matches the simulated value in figure 6.
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